1. Pressure difference height
(1013.25 − QNH) × 27
(1013.25 − 1002.00) × 27 = 304 ft
2. Pressure altitude
Field elevation + Pressure difference height
1411 + 304 = 1715 ft
3. Standard temperature
15 − (Pressure altitude × 2) / 1000
15 − (1715 × 2) / 1000 = 11.6 °C
4. Temperature difference
OAT − Standard temperature
35.0 − 11.6 = 23.4 °C
5. Temperature height
Temperature difference × 120
23.4 × 120 = 2812 ft
6. Density altitude
Pressure altitude + Temperature height
1715 + 2812 = 4526 ft
Aerotheo